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\frac{9}{5}=x^{2}
Divide both sides by 5.
x^{2}=\frac{9}{5}
Swap sides so that all variable terms are on the left hand side.
x=\frac{3\sqrt{5}}{5} x=-\frac{3\sqrt{5}}{5}
Take the square root of both sides of the equation.
\frac{9}{5}=x^{2}
Divide both sides by 5.
x^{2}=\frac{9}{5}
Swap sides so that all variable terms are on the left hand side.
x^{2}-\frac{9}{5}=0
Subtract \frac{9}{5} from both sides.
x=\frac{0±\sqrt{0^{2}-4\left(-\frac{9}{5}\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -\frac{9}{5} for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\left(-\frac{9}{5}\right)}}{2}
Square 0.
x=\frac{0±\sqrt{\frac{36}{5}}}{2}
Multiply -4 times -\frac{9}{5}.
x=\frac{0±\frac{6\sqrt{5}}{5}}{2}
Take the square root of \frac{36}{5}.
x=\frac{3\sqrt{5}}{5}
Now solve the equation x=\frac{0±\frac{6\sqrt{5}}{5}}{2} when ± is plus.
x=-\frac{3\sqrt{5}}{5}
Now solve the equation x=\frac{0±\frac{6\sqrt{5}}{5}}{2} when ± is minus.
x=\frac{3\sqrt{5}}{5} x=-\frac{3\sqrt{5}}{5}
The equation is now solved.