Solve 9=3u+1/2x-8*3^2

$$9 = 3 u + \frac { 1 } { 2 } x - 8 \times 3 ^ { 2 }$$

Solve for u

$$u=-\frac{x}{6}+27$$

Steps for Solving Linear Equation

Calculate 3 to the power of 2 and get 9.

$$9=3u+\frac{1}{2}x-8\times 9$$

Multiply 8 and 9 to get 72.

$$9=3u+\frac{1}{2}x-72$$

Swap sides so that all variable terms are on the left hand side.

$$3u+\frac{1}{2}x-72=9$$

Subtract \frac{1}{2}x from both sides.

$$3u-72=9-\frac{1}{2}x$$

Add 72 to both sides.

$$3u=9-\frac{1}{2}x+72$$

Add 9 and 72 to get 81.

$$3u=81-\frac{1}{2}x$$

The equation is in standard form.

$$3u=-\frac{x}{2}+81$$

Divide both sides by 3.

$$\frac{3u}{3}=\frac{-\frac{x}{2}+81}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$u=\frac{-\frac{x}{2}+81}{3}$$

Divide 81-\frac{x}{2} by 3.

$$u=-\frac{x}{6}+27$$

Solve for x

$$x=162-6u$$

Steps for Solving Linear Equation

Calculate 3 to the power of 2 and get 9.

$$9=3u+\frac{1}{2}x-8\times 9$$

Multiply 8 and 9 to get 72.

$$9=3u+\frac{1}{2}x-72$$

Swap sides so that all variable terms are on the left hand side.

$$3u+\frac{1}{2}x-72=9$$

Subtract 3u from both sides.

$$\frac{1}{2}x-72=9-3u$$

Add 72 to both sides.

$$\frac{1}{2}x=9-3u+72$$

Add 9 and 72 to get 81.

$$\frac{1}{2}x=81-3u$$

Multiply both sides by 2.

$$\frac{\frac{1}{2}x}{\frac{1}{2}}=\frac{81-3u}{\frac{1}{2}}$$

Dividing by \frac{1}{2} undoes the multiplication by \frac{1}{2}.

$$x=\frac{81-3u}{\frac{1}{2}}$$

Divide 81-3u by \frac{1}{2} by multiplying 81-3u by the reciprocal of \frac{1}{2}.

$$x=162-6u$$