Solve 9=z/1-xquadx

$$9 = \frac { z } { 1 - x } \quad x$$

Solve for x

$$x=\frac{9}{z+9}$$

$$z\neq 0\text{ and }z\neq -9$$

Steps for Solving Linear Equation

Variable x cannot be equal to 1 since division by zero is not defined. Multiply both sides of the equation by -x+1.

$$9\left(-x+1\right)=zx$$

Use the distributive property to multiply 9 by -x+1.

$$-9x+9=zx$$

Subtract zx from both sides.

$$-9x+9-zx=0$$

Subtract 9 from both sides. Anything subtracted from zero gives its negation.

$$-9x-zx=-9$$

Combine all terms containing x.

$$\left(-9-z\right)x=-9$$

The equation is in standard form.

$$\left(-z-9\right)x=-9$$

Divide both sides by -9-z.

$$\frac{\left(-z-9\right)x}{-z-9}=-\frac{9}{-z-9}$$

Dividing by -9-z undoes the multiplication by -9-z.

$$x=-\frac{9}{-z-9}$$

Divide -9 by -9-z.

$$x=\frac{9}{z+9}$$

Variable x cannot be equal to 1.

$$x=\frac{9}{z+9}\text{, }x\neq 1$$

Solve for z

$$z=-9+\frac{9}{x}$$

$$x\neq 1\text{ and }x\neq 0$$

Steps for Solving Linear Equation

Multiply both sides of the equation by -x+1.

$$9\left(-x+1\right)=zx$$

Use the distributive property to multiply 9 by -x+1.

$$-9x+9=zx$$

Swap sides so that all variable terms are on the left hand side.

$$zx=-9x+9$$

The equation is in standard form.

$$xz=9-9x$$

Divide both sides by x.

$$\frac{xz}{x}=\frac{9-9x}{x}$$

Dividing by x undoes the multiplication by x.

$$z=\frac{9-9x}{x}$$

Divide -9x+9 by x.

$$z=-9+\frac{9}{x}$$