Solve 9=b/a_{1}+b/a_{2}

$$9 = \frac { b } { a _ { 1 } } + \frac { b } { a _ { 2 } }$$

Solve for a_1

$$a_{1}=-\frac{a_{2}b}{b-9a_{2}}$$

$$a_{2}\neq 0\text{ and }b\neq 0\text{ and }b\neq 9a_{2}$$

Steps for Solving Linear Equation

Variable a_{1} cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by a_{1}a_{2}, the least common multiple of a_{1},a_{2}.

$$9a_{1}a_{2}=a_{2}b+a_{1}b$$

Subtract a_{1}b from both sides.

$$9a_{1}a_{2}-a_{1}b=a_{2}b$$

Combine all terms containing a_{1}.

$$\left(9a_{2}-b\right)a_{1}=a_{2}b$$

Divide both sides by 9a_{2}-b.

$$\frac{\left(9a_{2}-b\right)a_{1}}{9a_{2}-b}=\frac{a_{2}b}{9a_{2}-b}$$

Dividing by 9a_{2}-b undoes the multiplication by 9a_{2}-b.

$$a_{1}=\frac{a_{2}b}{9a_{2}-b}$$

Variable a_{1} cannot be equal to 0.

$$a_{1}=\frac{a_{2}b}{9a_{2}-b}\text{, }a_{1}\neq 0$$

Solve for a_2

$$a_{2}=-\frac{a_{1}b}{b-9a_{1}}$$

$$a_{1}\neq 0\text{ and }b\neq 0\text{ and }b\neq 9a_{1}$$

Steps for Solving Linear Equation

Variable a_{2} cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by a_{1}a_{2}, the least common multiple of a_{1},a_{2}.

$$9a_{1}a_{2}=a_{2}b+a_{1}b$$

Subtract a_{2}b from both sides.

$$9a_{1}a_{2}-a_{2}b=a_{1}b$$

Combine all terms containing a_{2}.

$$\left(9a_{1}-b\right)a_{2}=a_{1}b$$

Divide both sides by 9a_{1}-b.

$$\frac{\left(9a_{1}-b\right)a_{2}}{9a_{1}-b}=\frac{a_{1}b}{9a_{1}-b}$$

Dividing by 9a_{1}-b undoes the multiplication by 9a_{1}-b.

$$a_{2}=\frac{a_{1}b}{9a_{1}-b}$$

Variable a_{2} cannot be equal to 0.

$$a_{2}=\frac{a_{1}b}{9a_{1}-b}\text{, }a_{2}\neq 0$$