Solve for y
y=\frac{1}{3^{x}}
Solve for x (complex solution)
x=-\log_{3}\left(y\right)+\frac{2\pi n_{1}i}{\ln(3)}
n_{1}\in \mathrm{Z}
y\neq 0
Solve for x
x=-\log_{3}\left(y\right)
y>0
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9=y\times 3^{x+2}
Variable y cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by y.
y\times 3^{x+2}=9
Swap sides so that all variable terms are on the left hand side.
3^{x+2}y=9
The equation is in standard form.
\frac{3^{x+2}y}{3^{x+2}}=\frac{9}{3^{x+2}}
Divide both sides by 3^{x+2}.
y=\frac{9}{3^{x+2}}
Dividing by 3^{x+2} undoes the multiplication by 3^{x+2}.
y=\frac{1}{3^{x}}
Divide 9 by 3^{x+2}.
y=\frac{1}{3^{x}}\text{, }y\neq 0
Variable y cannot be equal to 0.
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