Solve 8x-72(1+05)=7x-7(1+05)x+700

$$8x-72(1+05)=7x-7(1+05)x+700$$

Solve for x

$$x = \frac{193}{2} = 96\frac{1}{2} = 96.5$$

Steps for Solving Linear Equation

Multiply 0 and 5 to get 0.

$$8x-72\left(1+0\right)=7x-7\left(1+0\times 5\right)x+700$$

Add 1 and 0 to get 1.

$$8x-72\times 1=7x-7\left(1+0\times 5\right)x+700$$

Multiply 72 and 1 to get 72.

$$8x-72=7x-7\left(1+0\times 5\right)x+700$$

Multiply 0 and 5 to get 0.

$$8x-72=7x-7\left(1+0\right)x+700$$

Add 1 and 0 to get 1.

$$8x-72=7x-7\times 1x+700$$

Multiply 7 and 1 to get 7.

$$8x-72=7x-7x+700$$

Combine 7x and -7x to get 0.

$$8x-72=0+700$$

Add 0 and 700 to get 700.

$$8x-72=700$$

Add 72 to both sides.

$$8x=700+72$$

Add 700 and 72 to get 772.

$$8x=772$$

Divide both sides by 8.

$$x=\frac{772}{8}$$

Reduce the fraction \frac{772}{8} to lowest terms by extracting and canceling out 4.

$$x=\frac{193}{2}$$