Solve 8x-3(x-4)=3(x-4)+6

$$8x-3(x-4)=3(x-4)+6$$

Solve for x

$$x=-9$$

Steps for Solving Linear Equation

Use the distributive property to multiply -3 by x-4.

$$8x-3x+12=3\left(x-4\right)+6$$

Combine 8x and -3x to get 5x.

$$5x+12=3\left(x-4\right)+6$$

Use the distributive property to multiply 3 by x-4.

$$5x+12=3x-12+6$$

Add -12 and 6 to get -6.

$$5x+12=3x-6$$

Subtract 3x from both sides.

$$5x+12-3x=-6$$

Combine 5x and -3x to get 2x.

$$2x+12=-6$$

Subtract 12 from both sides.

$$2x=-6-12$$

Subtract 12 from -6 to get -18.

$$2x=-18$$

Divide both sides by 2.

$$x=\frac{-18}{2}$$

Divide -18 by 2 to get -9.

$$x=-9$$