Solve for x
x=-\frac{9y}{8}+\frac{3}{4}
Solve for y
y=-\frac{8x}{9}+\frac{2}{3}
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8x=6-9y
Subtract 9y from both sides.
\frac{8x}{8}=\frac{6-9y}{8}
Divide both sides by 8.
x=\frac{6-9y}{8}
Dividing by 8 undoes the multiplication by 8.
x=-\frac{9y}{8}+\frac{3}{4}
Divide 6-9y by 8.
9y=6-8x
Subtract 8x from both sides.
\frac{9y}{9}=\frac{6-8x}{9}
Divide both sides by 9.
y=\frac{6-8x}{9}
Dividing by 9 undoes the multiplication by 9.
y=-\frac{8x}{9}+\frac{2}{3}
Divide 6-8x by 9.
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