Solve for x
x\geq \frac{39}{4}
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8x+6\geq 84
Multiply 6 and 14 to get 84.
8x\geq 84-6
Subtract 6 from both sides.
8x\geq 78
Subtract 6 from 84 to get 78.
x\geq \frac{78}{8}
Divide both sides by 8. Since 8 is positive, the inequality direction remains the same.
x\geq \frac{39}{4}
Reduce the fraction \frac{78}{8} to lowest terms by extracting and canceling out 2.
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