Solve for x
x\geq \frac{20}{11}
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8x+4\geq 24-3x
Add 16 and 8 to get 24.
8x+4+3x\geq 24
Add 3x to both sides.
11x+4\geq 24
Combine 8x and 3x to get 11x.
11x\geq 24-4
Subtract 4 from both sides.
11x\geq 20
Subtract 4 from 24 to get 20.
x\geq \frac{20}{11}
Divide both sides by 11. Since 11 is positive, the inequality direction remains the same.
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