Solve 8x+16x+23x-99x

$$8x+16x+23x-99x$$

Evaluate

$$-52x$$

Solution Steps

Combine 8x and 16x to get 24x.

$$24x+23x-99x$$

Combine 24x and 23x to get 47x.

$$47x-99x$$

Combine 47x and -99x to get -52x.

$$-52x$$

Differentiate w.r.t. x

$$-52$$

Steps Using Definition of a Derivative

Combine 8x and 16x to get 24x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(24x+23x-99x)$$

Combine 24x and 23x to get 47x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(47x-99x)$$

Combine 47x and -99x to get -52x.

$$\frac{\mathrm{d}}{\mathrm{d}x}(-52x)$$

The derivative of ax^{n} is nax^{n-1}.

$$-52x^{1-1}$$

Subtract 1 from 1.

$$-52x^{0}$$

For any term t except 0, t^{0}=1.

$$-52$$