Solve for a
a=\frac{23-2c-4b}{9}
Solve for b
b=-\frac{c}{2}-\frac{9a}{4}+\frac{23}{4}
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9a+4b+2c=23
Combine 8a and a to get 9a.
9a+2c=23-4b
Subtract 4b from both sides.
9a=23-4b-2c
Subtract 2c from both sides.
9a=23-2c-4b
The equation is in standard form.
\frac{9a}{9}=\frac{23-2c-4b}{9}
Divide both sides by 9.
a=\frac{23-2c-4b}{9}
Dividing by 9 undoes the multiplication by 9.
9a+4b+2c=23
Combine 8a and a to get 9a.
4b+2c=23-9a
Subtract 9a from both sides.
4b=23-9a-2c
Subtract 2c from both sides.
4b=23-2c-9a
The equation is in standard form.
\frac{4b}{4}=\frac{23-2c-9a}{4}
Divide both sides by 4.
b=\frac{23-2c-9a}{4}
Dividing by 4 undoes the multiplication by 4.
b=-\frac{c}{2}-\frac{9a}{4}+\frac{23}{4}
Divide 23-9a-2c by 4.
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