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x^{2}=152522525554715-89
Subtract 89 from both sides.
x^{2}=152522525554626
Subtract 89 from 152522525554715 to get 152522525554626.
x=\sqrt{152522525554626} x=-\sqrt{152522525554626}
Take the square root of both sides of the equation.
89+x^{2}-152522525554715=0
Subtract 152522525554715 from both sides.
-152522525554626+x^{2}=0
Subtract 152522525554715 from 89 to get -152522525554626.
x^{2}-152522525554626=0
Quadratic equations like this one, with an x^{2} term but no x term, can still be solved using the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, once they are put in standard form: ax^{2}+bx+c=0.
x=\frac{0±\sqrt{0^{2}-4\left(-152522525554626\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -152522525554626 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\left(-152522525554626\right)}}{2}
Square 0.
x=\frac{0±\sqrt{610090102218504}}{2}
Multiply -4 times -152522525554626.
x=\frac{0±2\sqrt{152522525554626}}{2}
Take the square root of 610090102218504.
x=\sqrt{152522525554626}
Now solve the equation x=\frac{0±2\sqrt{152522525554626}}{2} when ± is plus.
x=-\sqrt{152522525554626}
Now solve the equation x=\frac{0±2\sqrt{152522525554626}}{2} when ± is minus.
x=\sqrt{152522525554626} x=-\sqrt{152522525554626}
The equation is now solved.