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4\left(216+125u^{3}\right)
Factor out 4.
\left(5u+6\right)\left(25u^{2}-30u+36\right)
Consider 216+125u^{3}. Rewrite 216+125u^{3} as \left(5u\right)^{3}+6^{3}. The sum of cubes can be factored using the rule: a^{3}+b^{3}=\left(a+b\right)\left(a^{2}-ab+b^{2}\right).
4\left(5u+6\right)\left(25u^{2}-30u+36\right)
Rewrite the complete factored expression. Polynomial 25u^{2}-30u+36 is not factored since it does not have any rational roots.