Solve 8632+221j-58jleq-419j-7028

$$8632 + 221 j - 58 j \leq - 419 j - 7028$$

Solve for j

$$j\leq -\frac{2610}{97}$$

Solution Steps

Combine 221j and -58j to get 163j.

$$8632+163j\leq -419j-7028$$

Add 419j to both sides.

$$8632+163j+419j\leq -7028$$

Combine 163j and 419j to get 582j.

$$8632+582j\leq -7028$$

Subtract 8632 from both sides.

$$582j\leq -7028-8632$$

Subtract 8632 from -7028 to get -15660.

$$582j\leq -15660$$

Divide both sides by 582. Since 582 is positive, the inequality direction remains the same.

$$j\leq \frac{-15660}{582}$$

Reduce the fraction \frac{-15660}{582} to lowest terms by extracting and canceling out 6.

$$j\leq -\frac{2610}{97}$$