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880-4x^{2}=816
Swap sides so that all variable terms are on the left hand side.
-4x^{2}=816-880
Subtract 880 from both sides.
-4x^{2}=-64
Subtract 880 from 816 to get -64.
x^{2}=\frac{-64}{-4}
Divide both sides by -4.
x^{2}=16
Divide -64 by -4 to get 16.
x=4 x=-4
Take the square root of both sides of the equation.
880-4x^{2}=816
Swap sides so that all variable terms are on the left hand side.
880-4x^{2}-816=0
Subtract 816 from both sides.
64-4x^{2}=0
Subtract 816 from 880 to get 64.
-4x^{2}+64=0
Quadratic equations like this one, with an x^{2} term but no x term, can still be solved using the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, once they are put in standard form: ax^{2}+bx+c=0.
x=\frac{0±\sqrt{0^{2}-4\left(-4\right)\times 64}}{2\left(-4\right)}
This equation is in standard form: ax^{2}+bx+c=0. Substitute -4 for a, 0 for b, and 64 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\left(-4\right)\times 64}}{2\left(-4\right)}
Square 0.
x=\frac{0±\sqrt{16\times 64}}{2\left(-4\right)}
Multiply -4 times -4.
x=\frac{0±\sqrt{1024}}{2\left(-4\right)}
Multiply 16 times 64.
x=\frac{0±32}{2\left(-4\right)}
Take the square root of 1024.
x=\frac{0±32}{-8}
Multiply 2 times -4.
x=-4
Now solve the equation x=\frac{0±32}{-8} when ± is plus. Divide 32 by -8.
x=4
Now solve the equation x=\frac{0±32}{-8} when ± is minus. Divide -32 by -8.
x=-4 x=4
The equation is now solved.