Factor
3\left(3x-y\right)\left(9x^{2}+3xy+y^{2}\right)
Evaluate
81x^{3}-3y^{3}
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3\left(27x^{3}-y^{3}\right)
Factor out 3.
\left(3x-y\right)\left(9x^{2}+3xy+y^{2}\right)
Consider 27x^{3}-y^{3}. Rewrite 27x^{3}-y^{3} as \left(3x\right)^{3}-y^{3}. The difference of cubes can be factored using the rule: a^{3}-b^{3}=\left(a-b\right)\left(a^{2}+ab+b^{2}\right).
3\left(3x-y\right)\left(9x^{2}+3xy+y^{2}\right)
Rewrite the complete factored expression.
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