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\left(9p^{4}-10\right)\left(9p^{4}+10\right)
Rewrite 81p^{8}-100 as \left(9p^{4}\right)^{2}-10^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right). The following polynomials are not factored since they do not have any rational roots: 9p^{4}-10,9p^{4}+10.