Solve 81a^2b^2div9a^2b*7ab^2

$$81 a ^ { 2 } b ^ { 2 } \div 9 a ^ { 2 } b \times 7 a b ^ { 2 }$$

Evaluate

$$63\left(ab\right)^{5}$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 2 and 1 to get 3.

$$\frac{81a^{2}b^{2}}{9}a^{3}b\times 7b^{2}$$

To multiply powers of the same base, add their exponents. Add 1 and 2 to get 3.

$$\frac{81a^{2}b^{2}}{9}a^{3}b^{3}\times 7$$

Divide 81a^{2}b^{2} by 9 to get 9a^{2}b^{2}.

$$9a^{2}b^{2}a^{3}b^{3}\times 7$$

To multiply powers of the same base, add their exponents. Add 2 and 3 to get 5.

$$9a^{5}b^{2}b^{3}\times 7$$

To multiply powers of the same base, add their exponents. Add 2 and 3 to get 5.

$$9a^{5}b^{5}\times 7$$

Multiply 9 and 7 to get 63.

$$63a^{5}b^{5}$$

Differentiate w.r.t. a

$$315a^{4}b^{5}$$