Solve 81^3+3*9^6+4*27^4

$$81 ^ { 3 } + 3 \cdot 9 ^ { 6 } + 4 \cdot 27 ^ { 4 }$$

Evaluate

$$4251528$$

Solution Steps

Calculate 81 to the power of 3 and get 531441.

$$531441+3\times 9^{6}+4\times 27^{4}$$

Calculate 9 to the power of 6 and get 531441.

$$531441+3\times 531441+4\times 27^{4}$$

Multiply 3 and 531441 to get 1594323.

$$531441+1594323+4\times 27^{4}$$

Add 531441 and 1594323 to get 2125764.

$$2125764+4\times 27^{4}$$

Calculate 27 to the power of 4 and get 531441.

$$2125764+4\times 531441$$

Multiply 4 and 531441 to get 2125764.

$$2125764+2125764$$

Add 2125764 and 2125764 to get 4251528.

$$4251528$$

Factor

$$2^{3}\times 3^{12}$$