Solve 80x-01x^2-500+20x

$$80x-01 { x }^{ 2 } -500+20x$$

Evaluate

$$100\left(x-5\right)$$

Solution Steps

Multiply 0 and 1 to get 0.

$$80x-0x^{2}-500+20x$$

Anything times zero gives zero.

$$80x-0-500+20x$$

Multiply -1 and 0 to get 0.

$$80x+0-500+20x$$

Anything plus zero gives itself.

$$80x-500+20x$$

Combine 80x and 20x to get 100x.

$$100x-500$$

Factor

$$100\left(x-5\right)$$

Solution Steps

Factor out 20.

$$20\left(4x+0-25+x\right)$$

Consider 4x-25+x. Multiply and combine like terms.

$$5x-25$$

Consider 5x-25. Factor out 5.

$$5\left(x-5\right)$$

Rewrite the complete factored expression.

$$100\left(x-5\right)$$