Solve 80ab=72b

$$80 a b = 72 b$$

Solve for a

$$\left\{\begin{matrix}\\a=\frac{9}{10}=0.9\text{, }&\text{unconditionally}\\a\in \mathrm{R}\text{, }&b=0\end{matrix}\right.$$

Steps for Solving Linear Equation

The equation is in standard form.

$$80ba=72b$$

Divide both sides by 80b.

$$\frac{80ba}{80b}=\frac{72b}{80b}$$

Dividing by 80b undoes the multiplication by 80b.

$$a=\frac{72b}{80b}$$

Divide 72b by 80b.

$$a=\frac{9}{10}$$

Solve for b

$$\left\{\begin{matrix}\\b=0\text{, }&\text{unconditionally}\\b\in \mathrm{R}\text{, }&a=\frac{9}{10}\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract 72b from both sides.

$$80ab-72b=0$$

Combine all terms containing b.

$$\left(80a-72\right)b=0$$

Divide 0 by 80a-72.

$$b=0$$