Solve 80(x+1)^2=1352

$$80 ( x + 1 ) ^ { 2 } = 1352$$

Solve for x

$$x=\frac{13\sqrt{10}}{10}-1\approx 3.110960958$$

$$x=-\frac{13\sqrt{10}}{10}-1\approx -5.110960958$$

Steps by Finding Square Root

Divide both sides by 80.

$$\frac{80\left(x+1\right)^{2}}{80}=\frac{1352}{80}$$

Dividing by 80 undoes the multiplication by 80.

$$\left(x+1\right)^{2}=\frac{1352}{80}$$

Reduce the fraction \frac{1352}{80} to lowest terms by extracting and canceling out 8.

$$\left(x+1\right)^{2}=\frac{169}{10}$$

Take the square root of both sides of the equation.

$$x+1=\frac{13\sqrt{10}}{10} x+1=-\frac{13\sqrt{10}}{10}$$

Subtract 1 from both sides of the equation.

$$x+1-1=\frac{13\sqrt{10}}{10}-1 x+1-1=-\frac{13\sqrt{10}}{10}-1$$

Subtracting 1 from itself leaves 0.

$$x=\frac{13\sqrt{10}}{10}-1 x=-\frac{13\sqrt{10}}{10}-1$$