Solve 80(x+1)^2=135.2

$$80 ( x + 1 ) ^ { 2 } = 135.2$$

Solve for x

$$x=0.3$$

$$x=-2.3$$

Steps by Finding Square Root

Divide both sides by 80.

$$\frac{80\left(x+1\right)^{2}}{80}=\frac{135.2}{80}$$

Dividing by 80 undoes the multiplication by 80.

$$\left(x+1\right)^{2}=\frac{135.2}{80}$$

Divide 135.2 by 80.

$$\left(x+1\right)^{2}=1.69$$

Take the square root of both sides of the equation.

$$x+1=\frac{13}{10} x+1=-\frac{13}{10}$$

Subtract 1 from both sides of the equation.

$$x+1-1=\frac{13}{10}-1 x+1-1=-\frac{13}{10}-1$$

Subtracting 1 from itself leaves 0.

$$x=\frac{13}{10}-1 x=-\frac{13}{10}-1$$

Subtract 1 from \frac{13}{10}.

$$x=\frac{3}{10}$$

Subtract 1 from -\frac{13}{10}.

$$x=-\frac{23}{10}$$

The equation is now solved.

$$x=\frac{3}{10} x=-\frac{23}{10}$$