Solve 80(1+x)^2=115.2

$$80 ( 1 + x ) ^ { 2 } = 115.2$$

Solve for x

$$x=0.2$$

$$x=-2.2$$

Steps by Finding Square Root

Divide both sides by 80.

$$\frac{80\left(x+1\right)^{2}}{80}=\frac{115.2}{80}$$

Dividing by 80 undoes the multiplication by 80.

$$\left(x+1\right)^{2}=\frac{115.2}{80}$$

Divide 115.2 by 80.

$$\left(x+1\right)^{2}=1.44$$

Take the square root of both sides of the equation.

$$x+1=\frac{6}{5} x+1=-\frac{6}{5}$$

Subtract 1 from both sides of the equation.

$$x+1-1=\frac{6}{5}-1 x+1-1=-\frac{6}{5}-1$$

Subtracting 1 from itself leaves 0.

$$x=\frac{6}{5}-1 x=-\frac{6}{5}-1$$

Subtract 1 from \frac{6}{5}.

$$x=\frac{1}{5}$$

Subtract 1 from -\frac{6}{5}.

$$x=-\frac{11}{5}$$

The equation is now solved.

$$x=\frac{1}{5} x=-\frac{11}{5}$$