Solve 80*55*70^2+120*sin60^circ

$$80 \times 55 \times 70 ^ { 2 } + 120 \times \sin 60 ^ { \circ }$$

Evaluate

$$20\left(3\sqrt{3}+1078000\right)\approx 21560103.923048455$$

Solution Steps

Multiply 80 and 55 to get 4400.

$$4400\times 70^{2}+120\sin(60)$$

Calculate 70 to the power of 2 and get 4900.

$$4400\times 4900+120\sin(60)$$

Multiply 4400 and 4900 to get 21560000.

$$21560000+120\sin(60)$$

Get the value of \sin(60) from trigonometric values table.

$$21560000+120\times \frac{\sqrt{3}}{2}$$

Cancel out 2, the greatest common factor in 120 and 2.

$$21560000+60\sqrt{3}$$