Solve for t
t=-\lfloor \cos(x)\rfloor +4
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-2t=2\lfloor 1\cos(x)\rfloor -8
Subtract 8 from both sides.
-2t=2\lfloor \cos(x)\rfloor -8
The equation is in standard form.
\frac{-2t}{-2}=\frac{2\left(\lfloor \cos(x)\rfloor -4\right)}{-2}
Divide both sides by -2.
t=\frac{2\left(\lfloor \cos(x)\rfloor -4\right)}{-2}
Dividing by -2 undoes the multiplication by -2.
t=-\lfloor \cos(x)\rfloor +4
Divide 2\left(\lfloor \cos(x)\rfloor -4\right) by -2.
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