Solve 8-2-2-4-3-2^2-4-4^2

$$8-2-2-4-3 { -2 }^{ 2 } -4- { 4 }^{ 2 }$$

Evaluate

$$-32$$

Solution Steps

Subtract 2 from 8 to get 6.

$$6-2-4-3\left(-2\right)^{2}-4-4^{2}$$

Subtract 2 from 6 to get 4.

$$4-4-3\left(-2\right)^{2}-4-4^{2}$$

Subtract 4 from 4 to get 0.

$$0-3\left(-2\right)^{2}-4-4^{2}$$

Calculate -2 to the power of 2 and get 4.

$$0-3\times 4-4-4^{2}$$

Multiply 3 and 4 to get 12.

$$0-12-4-4^{2}$$

Subtract 12 from 0 to get -12.

$$-12-4-4^{2}$$

Subtract 4 from -12 to get -16.

$$-16-4^{2}$$

Calculate 4 to the power of 2 and get 16.

$$-16-16$$

Subtract 16 from -16 to get -32.

$$-32$$

Factor

$$-32$$