Solve 8-(-22/3)+7-(-11/3)+5

$$8-(- 2 \frac { 2 } { 3 } )+7-(- 1 \frac { 1 } { 3 } )+5$$

Evaluate

$$24$$

Solution Steps

Multiply 2 and 3 to get 6.

$$8-\left(-\frac{6+2}{3}\right)+7-\left(-\frac{1\times 3+1}{3}\right)+5$$

Add 6 and 2 to get 8.

$$8-\left(-\frac{8}{3}\right)+7-\left(-\frac{1\times 3+1}{3}\right)+5$$

The opposite of -\frac{8}{3} is \frac{8}{3}.

$$8+\frac{8}{3}+7-\left(-\frac{1\times 3+1}{3}\right)+5$$

Convert 8 to fraction \frac{24}{3}.

$$\frac{24}{3}+\frac{8}{3}+7-\left(-\frac{1\times 3+1}{3}\right)+5$$

Since \frac{24}{3} and \frac{8}{3} have the same denominator, add them by adding their numerators.

$$\frac{24+8}{3}+7-\left(-\frac{1\times 3+1}{3}\right)+5$$

Add 24 and 8 to get 32.

$$\frac{32}{3}+7-\left(-\frac{1\times 3+1}{3}\right)+5$$

Convert 7 to fraction \frac{21}{3}.

$$\frac{32}{3}+\frac{21}{3}-\left(-\frac{1\times 3+1}{3}\right)+5$$

Since \frac{32}{3} and \frac{21}{3} have the same denominator, add them by adding their numerators.

$$\frac{32+21}{3}-\left(-\frac{1\times 3+1}{3}\right)+5$$

Add 32 and 21 to get 53.

$$\frac{53}{3}-\left(-\frac{1\times 3+1}{3}\right)+5$$

Multiply 1 and 3 to get 3.

$$\frac{53}{3}-\left(-\frac{3+1}{3}\right)+5$$

Add 3 and 1 to get 4.

$$\frac{53}{3}-\left(-\frac{4}{3}\right)+5$$

The opposite of -\frac{4}{3} is \frac{4}{3}.

$$\frac{53}{3}+\frac{4}{3}+5$$

Since \frac{53}{3} and \frac{4}{3} have the same denominator, add them by adding their numerators.

$$\frac{53+4}{3}+5$$

Add 53 and 4 to get 57.

$$\frac{57}{3}+5$$

Divide 57 by 3 to get 19.

$$19+5$$

Add 19 and 5 to get 24.

$$24$$

Factor

$$2^{3}\times 3$$