Solve 8-8/3-16-8-64/3-8/3

$$8- \frac{ 8 }{ 3 } -16-8- \frac{ 64 }{ 3 } - \frac{ 8 }{ 3 }$$

Evaluate

$$-\frac{128}{3}\approx -42.666666667$$

Solution Steps

Convert 8 to fraction \frac{24}{3}.

$$\frac{24}{3}-\frac{8}{3}-16-8-\frac{64}{3}-\frac{8}{3}$$

Since \frac{24}{3} and \frac{8}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{24-8}{3}-16-8-\frac{64}{3}-\frac{8}{3}$$

Subtract 8 from 24 to get 16.

$$\frac{16}{3}-16-8-\frac{64}{3}-\frac{8}{3}$$

Convert 16 to fraction \frac{48}{3}.

$$\frac{16}{3}-\frac{48}{3}-8-\frac{64}{3}-\frac{8}{3}$$

Since \frac{16}{3} and \frac{48}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{16-48}{3}-8-\frac{64}{3}-\frac{8}{3}$$

Subtract 48 from 16 to get -32.

$$-\frac{32}{3}-8-\frac{64}{3}-\frac{8}{3}$$

Convert 8 to fraction \frac{24}{3}.

$$-\frac{32}{3}-\frac{24}{3}-\frac{64}{3}-\frac{8}{3}$$

Since -\frac{32}{3} and \frac{24}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-32-24}{3}-\frac{64}{3}-\frac{8}{3}$$

Subtract 24 from -32 to get -56.

$$-\frac{56}{3}-\frac{64}{3}-\frac{8}{3}$$

Since -\frac{56}{3} and \frac{64}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-56-64}{3}-\frac{8}{3}$$

Subtract 64 from -56 to get -120.

$$\frac{-120}{3}-\frac{8}{3}$$

Divide -120 by 3 to get -40.

$$-40-\frac{8}{3}$$

Convert -40 to fraction -\frac{120}{3}.

$$-\frac{120}{3}-\frac{8}{3}$$

Since -\frac{120}{3} and \frac{8}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-120-8}{3}$$

Subtract 8 from -120 to get -128.

$$-\frac{128}{3}$$

Factor

$$-\frac{128}{3} = -42\frac{2}{3} = -42.666666666666664$$