Solve 8-1/3*1/3+4=-1

$$8- \frac{ 1 }{ 3 } \times \frac{ 1 }{ 3 } +4=-1$$

Verify

Solution Steps

Multiply \frac{1}{3} times \frac{1}{3} by multiplying numerator times numerator and denominator times denominator.

$$8-\frac{1\times 1}{3\times 3}+4=-1$$

Do the multiplications in the fraction \frac{1\times 1}{3\times 3}.

$$8-\frac{1}{9}+4=-1$$

Convert 8 to fraction \frac{72}{9}.

$$\frac{72}{9}-\frac{1}{9}+4=-1$$

Since \frac{72}{9} and \frac{1}{9} have the same denominator, subtract them by subtracting their numerators.

$$\frac{72-1}{9}+4=-1$$

Subtract 1 from 72 to get 71.

$$\frac{71}{9}+4=-1$$

Convert 4 to fraction \frac{36}{9}.

$$\frac{71}{9}+\frac{36}{9}=-1$$

Since \frac{71}{9} and \frac{36}{9} have the same denominator, add them by adding their numerators.

$$\frac{71+36}{9}=-1$$

Add 71 and 36 to get 107.

$$\frac{107}{9}=-1$$

Convert -1 to fraction -\frac{9}{9}.

$$\frac{107}{9}=-\frac{9}{9}$$

Compare \frac{107}{9} and -\frac{9}{9}.

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