Solve 8-frac{sqrt{8^2-4*12}}{4/4{frac{4/4}}}

$$8- \frac{ \sqrt{ { 8 }^{ 2 } -4 \cdot 12 } }{ \frac{ 4 }{ \frac{ 4 }{ \frac{ 4 }{ 4 } } } }$$

Evaluate

$$4$$

Solution Steps

Divide 4 by 4 to get 1.

$$8-\frac{\sqrt{8^{2}-4\times 12}}{\frac{4}{\frac{4}{1}}}$$

Calculate 8 to the power of 2 and get 64.

$$8-\frac{\sqrt{64-4\times 12}}{\frac{4}{\frac{4}{1}}}$$

Multiply 4 and 12 to get 48.

$$8-\frac{\sqrt{64-48}}{\frac{4}{\frac{4}{1}}}$$

Subtract 48 from 64 to get 16.

$$8-\frac{\sqrt{16}}{\frac{4}{\frac{4}{1}}}$$

Calculate the square root of 16 and get 4.

$$8-\frac{4}{\frac{4}{\frac{4}{1}}}$$

Divide 4 by \frac{4}{1} by multiplying 4 by the reciprocal of \frac{4}{1}.

$$8-\frac{4}{\frac{4}{4}}$$

Divide 4 by 4 to get 1.

$$8-\frac{4}{1}$$

Anything divided by one gives itself.

$$8-4$$

Subtract 4 from 8 to get 4.

$$4$$

Factor

$$2^{2}$$