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8\times \frac{1}{12}-8y+15y=1
Use the distributive property to multiply 8 by \frac{1}{12}-y.
\frac{8}{12}-8y+15y=1
Multiply 8 and \frac{1}{12} to get \frac{8}{12}.
\frac{2}{3}-8y+15y=1
Reduce the fraction \frac{8}{12} to lowest terms by extracting and canceling out 4.
\frac{2}{3}+7y=1
Combine -8y and 15y to get 7y.
7y=1-\frac{2}{3}
Subtract \frac{2}{3} from both sides.
7y=\frac{3}{3}-\frac{2}{3}
Convert 1 to fraction \frac{3}{3}.
7y=\frac{3-2}{3}
Since \frac{3}{3} and \frac{2}{3} have the same denominator, subtract them by subtracting their numerators.
7y=\frac{1}{3}
Subtract 2 from 3 to get 1.
y=\frac{\frac{1}{3}}{7}
Divide both sides by 7.
y=\frac{1}{3\times 7}
Express \frac{\frac{1}{3}}{7} as a single fraction.
y=\frac{1}{21}
Multiply 3 and 7 to get 21.