Solve 8+6*9-612/3(35+7div6)

$$8+6 \times 9-6 \frac{ 12 }{ 3 } (35+7 \div 6)$$

Evaluate

$$-\frac{899}{3}\approx -299.666666667$$

Solution Steps

Multiply 6 and 9 to get 54.

$$8+54-\frac{6\times 3+12}{3}\left(35+\frac{7}{6}\right)$$

Add 8 and 54 to get 62.

$$62-\frac{6\times 3+12}{3}\left(35+\frac{7}{6}\right)$$

Multiply 6 and 3 to get 18.

$$62-\frac{18+12}{3}\left(35+\frac{7}{6}\right)$$

Add 18 and 12 to get 30.

$$62-\frac{30}{3}\left(35+\frac{7}{6}\right)$$

Divide 30 by 3 to get 10.

$$62-10\left(35+\frac{7}{6}\right)$$

Convert 35 to fraction \frac{210}{6}.

$$62-10\left(\frac{210}{6}+\frac{7}{6}\right)$$

Since \frac{210}{6} and \frac{7}{6} have the same denominator, add them by adding their numerators.

$$62-10\times \frac{210+7}{6}$$

Add 210 and 7 to get 217.

$$62-10\times \frac{217}{6}$$

Express 10\times \frac{217}{6} as a single fraction.

$$62-\frac{10\times 217}{6}$$

Multiply 10 and 217 to get 2170.

$$62-\frac{2170}{6}$$

Reduce the fraction \frac{2170}{6} to lowest terms by extracting and canceling out 2.

$$62-\frac{1085}{3}$$

Convert 62 to fraction \frac{186}{3}.

$$\frac{186}{3}-\frac{1085}{3}$$

Since \frac{186}{3} and \frac{1085}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{186-1085}{3}$$

Subtract 1085 from 186 to get -899.

$$-\frac{899}{3}$$

Factor

$$-\frac{899}{3} = -299\frac{2}{3} = -299.6666666666667$$