Solve for x
x=-\frac{1}{8}+\frac{675}{8y}
y\neq 0
Solve for y
y=\frac{675}{8x+1}
x\neq -\frac{1}{8}
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8xy=675-y
Subtract y from both sides.
8yx=675-y
The equation is in standard form.
\frac{8yx}{8y}=\frac{675-y}{8y}
Divide both sides by 8y.
x=\frac{675-y}{8y}
Dividing by 8y undoes the multiplication by 8y.
x=-\frac{1}{8}+\frac{675}{8y}
Divide 675-y by 8y.
\left(8x+1\right)y=675
Combine all terms containing y.
\frac{\left(8x+1\right)y}{8x+1}=\frac{675}{8x+1}
Divide both sides by 8x+1.
y=\frac{675}{8x+1}
Dividing by 8x+1 undoes the multiplication by 8x+1.
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