Solve for x
x=\frac{3\left(y-1\right)}{4}
Solve for y
y=\frac{4x}{3}+1
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8x=-6+6y
Add 6y to both sides.
8x=6y-6
The equation is in standard form.
\frac{8x}{8}=\frac{6y-6}{8}
Divide both sides by 8.
x=\frac{6y-6}{8}
Dividing by 8 undoes the multiplication by 8.
x=\frac{3y-3}{4}
Divide -6+6y by 8.
-6y=-6-8x
Subtract 8x from both sides.
-6y=-8x-6
The equation is in standard form.
\frac{-6y}{-6}=\frac{-8x-6}{-6}
Divide both sides by -6.
y=\frac{-8x-6}{-6}
Dividing by -6 undoes the multiplication by -6.
y=\frac{4x}{3}+1
Divide -6-8x by -6.
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Limits
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