Solve for x
x=\frac{5\left(y+2\right)}{8}
Solve for y
y=\frac{8x}{5}-2
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8x=10+5y
Add 5y to both sides.
8x=5y+10
The equation is in standard form.
\frac{8x}{8}=\frac{5y+10}{8}
Divide both sides by 8.
x=\frac{5y+10}{8}
Dividing by 8 undoes the multiplication by 8.
x=\frac{5y}{8}+\frac{5}{4}
Divide 10+5y by 8.
-5y=10-8x
Subtract 8x from both sides.
\frac{-5y}{-5}=\frac{10-8x}{-5}
Divide both sides by -5.
y=\frac{10-8x}{-5}
Dividing by -5 undoes the multiplication by -5.
y=\frac{8x}{5}-2
Divide 10-8x by -5.
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