Solve 8x-4x*2+4x

$$8 x - 4 x \times 2 + 4 x$$

Evaluate

$$4x$$

Solution Steps

Multiply 4 and 2 to get 8.

$$8x-8x+4x$$

Combine 8x and -8x to get 0.

$$0+4x$$

Anything plus zero gives itself.

$$4x$$

Differentiate w.r.t. x

$$4$$

Steps Using Definition of a Derivative

Multiply 4 and 2 to get 8.

$$\frac{\mathrm{d}}{\mathrm{d}x}(8x-8x+4x)$$

Combine 8x and -8x to get 0.

$$\frac{\mathrm{d}}{\mathrm{d}x}(0+4x)$$

Anything plus zero gives itself.

$$\frac{\mathrm{d}}{\mathrm{d}x}(4x)$$

The derivative of ax^{n} is nax^{n-1}.

$$4x^{1-1}$$

Subtract 1 from 1.

$$4x^{0}$$

For any term t except 0, t^{0}=1.

$$4\times 1$$

For any term t, t\times 1=t and 1t=t.

$$4$$