Solve for x
x=\frac{y}{4}+\frac{3}{8}
Solve for y
y=4x-\frac{3}{2}
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8x=3+2y
Add 2y to both sides.
8x=2y+3
The equation is in standard form.
\frac{8x}{8}=\frac{2y+3}{8}
Divide both sides by 8.
x=\frac{2y+3}{8}
Dividing by 8 undoes the multiplication by 8.
x=\frac{y}{4}+\frac{3}{8}
Divide 3+2y by 8.
-2y=3-8x
Subtract 8x from both sides.
\frac{-2y}{-2}=\frac{3-8x}{-2}
Divide both sides by -2.
y=\frac{3-8x}{-2}
Dividing by -2 undoes the multiplication by -2.
y=4x-\frac{3}{2}
Divide 3-8x by -2.
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