Solve for B
B=\frac{8x-1}{3}
Solve for x
x=\frac{3B+1}{8}
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3B=8x-1
Swap sides so that all variable terms are on the left hand side.
\frac{3B}{3}=\frac{8x-1}{3}
Divide both sides by 3.
B=\frac{8x-1}{3}
Dividing by 3 undoes the multiplication by 3.
8x=3B+1
Add 1 to both sides.
\frac{8x}{8}=\frac{3B+1}{8}
Divide both sides by 8.
x=\frac{3B+1}{8}
Dividing by 8 undoes the multiplication by 8.
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