Solve 8x-2/3=11/2x-4

$$8 x - \frac { 2 } { 3 } = \frac { 11 } { 2 } x - 4$$

Solve for x

$$x = -\frac{4}{3} = -1\frac{1}{3} \approx -1.333333333$$

Steps for Solving Linear Equation

Subtract \frac{11}{2}x from both sides.

$$8x-\frac{2}{3}-\frac{11}{2}x=-4$$

Combine 8x and -\frac{11}{2}x to get \frac{5}{2}x.

$$\frac{5}{2}x-\frac{2}{3}=-4$$

Add \frac{2}{3} to both sides.

$$\frac{5}{2}x=-4+\frac{2}{3}$$

Convert -4 to fraction -\frac{12}{3}.

$$\frac{5}{2}x=-\frac{12}{3}+\frac{2}{3}$$

Since -\frac{12}{3} and \frac{2}{3} have the same denominator, add them by adding their numerators.

$$\frac{5}{2}x=\frac{-12+2}{3}$$

Add -12 and 2 to get -10.

$$\frac{5}{2}x=-\frac{10}{3}$$

Multiply both sides by \frac{2}{5}, the reciprocal of \frac{5}{2}.

$$x=-\frac{10}{3}\times \frac{2}{5}$$

Multiply -\frac{10}{3} times \frac{2}{5} by multiplying numerator times numerator and denominator times denominator.

$$x=\frac{-10\times 2}{3\times 5}$$

Do the multiplications in the fraction \frac{-10\times 2}{3\times 5}.

$$x=\frac{-20}{15}$$

Reduce the fraction \frac{-20}{15} to lowest terms by extracting and canceling out 5.

$$x=-\frac{4}{3}$$