Solve 8x-1/4*3=45/4

$$8 x - \frac { 1 } { 4 } \times 3 = \frac { 45 } { 4 }$$

Solve for x

$$x = \frac{3}{2} = 1\frac{1}{2} = 1.5$$

Steps for Solving Linear Equation

Multiply \frac{1}{4} and 3 to get \frac{3}{4}.

$$8x-\frac{3}{4}=\frac{45}{4}$$

Add \frac{3}{4} to both sides.

$$8x=\frac{45}{4}+\frac{3}{4}$$

Since \frac{45}{4} and \frac{3}{4} have the same denominator, add them by adding their numerators.

$$8x=\frac{45+3}{4}$$

Add 45 and 3 to get 48.

$$8x=\frac{48}{4}$$

Divide 48 by 4 to get 12.

$$8x=12$$

Divide both sides by 8.

$$x=\frac{12}{8}$$

Reduce the fraction \frac{12}{8} to lowest terms by extracting and canceling out 4.

$$x=\frac{3}{2}$$