Solve 8x^4+7x^3+5x^2+4z=8

$$8 x ^ { 4 } + 7 x ^ { 3 } + 5 x ^ { 2 } + 4 z = 8$$

Solve for z

$$z=-2x^{4}-\frac{7x^{3}}{4}-\frac{5x^{2}}{4}+2$$

Steps for Solving Linear Equation

Subtract 8x^{4} from both sides.

$$7x^{3}+5x^{2}+4z=8-8x^{4}$$

Subtract 7x^{3} from both sides.

$$5x^{2}+4z=8-8x^{4}-7x^{3}$$

Subtract 5x^{2} from both sides.

$$4z=8-8x^{4}-7x^{3}-5x^{2}$$

The equation is in standard form.

$$4z=8-5x^{2}-7x^{3}-8x^{4}$$

Divide both sides by 4.

$$\frac{4z}{4}=\frac{8-5x^{2}-7x^{3}-8x^{4}}{4}$$

Dividing by 4 undoes the multiplication by 4.

$$z=\frac{8-5x^{2}-7x^{3}-8x^{4}}{4}$$

Divide 8-8x^{4}-7x^{3}-5x^{2} by 4.

$$z=-2x^{4}-\frac{7x^{3}}{4}-\frac{5x^{2}}{4}+2$$