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\left(2x-3y\right)\left(4x^{2}+6xy+9y^{2}\right)
Rewrite 8x^{3}-27y^{3} as \left(2x\right)^{3}-\left(3y\right)^{3}. The difference of cubes can be factored using the rule: a^{3}-b^{3}=\left(a-b\right)\left(a^{2}+ab+b^{2}\right).