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4\left(2x^{2}-3x-2\right)
Factor out 4.
a+b=-3 ab=2\left(-2\right)=-4
Consider 2x^{2}-3x-2. Factor the expression by grouping. First, the expression needs to be rewritten as 2x^{2}+ax+bx-2. To find a and b, set up a system to be solved.
1,-4 2,-2
Since ab is negative, a and b have the opposite signs. Since a+b is negative, the negative number has greater absolute value than the positive. List all such integer pairs that give product -4.
1-4=-3 2-2=0
Calculate the sum for each pair.
a=-4 b=1
The solution is the pair that gives sum -3.
\left(2x^{2}-4x\right)+\left(x-2\right)
Rewrite 2x^{2}-3x-2 as \left(2x^{2}-4x\right)+\left(x-2\right).
2x\left(x-2\right)+x-2
Factor out 2x in 2x^{2}-4x.
\left(x-2\right)\left(2x+1\right)
Factor out common term x-2 by using distributive property.
4\left(x-2\right)\left(2x+1\right)
Rewrite the complete factored expression.
8x^{2}-12x-8=0
Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where x_{1} and x_{2} are the solutions of the quadratic equation ax^{2}+bx+c=0.
x=\frac{-\left(-12\right)±\sqrt{\left(-12\right)^{2}-4\times 8\left(-8\right)}}{2\times 8}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-\left(-12\right)±\sqrt{144-4\times 8\left(-8\right)}}{2\times 8}
Square -12.
x=\frac{-\left(-12\right)±\sqrt{144-32\left(-8\right)}}{2\times 8}
Multiply -4 times 8.
x=\frac{-\left(-12\right)±\sqrt{144+256}}{2\times 8}
Multiply -32 times -8.
x=\frac{-\left(-12\right)±\sqrt{400}}{2\times 8}
Add 144 to 256.
x=\frac{-\left(-12\right)±20}{2\times 8}
Take the square root of 400.
x=\frac{12±20}{2\times 8}
The opposite of -12 is 12.
x=\frac{12±20}{16}
Multiply 2 times 8.
x=\frac{32}{16}
Now solve the equation x=\frac{12±20}{16} when ± is plus. Add 12 to 20.
x=2
Divide 32 by 16.
x=-\frac{8}{16}
Now solve the equation x=\frac{12±20}{16} when ± is minus. Subtract 20 from 12.
x=-\frac{1}{2}
Reduce the fraction \frac{-8}{16} to lowest terms by extracting and canceling out 8.
8x^{2}-12x-8=8\left(x-2\right)\left(x-\left(-\frac{1}{2}\right)\right)
Factor the original expression using ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Substitute 2 for x_{1} and -\frac{1}{2} for x_{2}.
8x^{2}-12x-8=8\left(x-2\right)\left(x+\frac{1}{2}\right)
Simplify all the expressions of the form p-\left(-q\right) to p+q.
8x^{2}-12x-8=8\left(x-2\right)\times \frac{2x+1}{2}
Add \frac{1}{2} to x by finding a common denominator and adding the numerators. Then reduce the fraction to lowest terms if possible.
8x^{2}-12x-8=4\left(x-2\right)\left(2x+1\right)
Cancel out 2, the greatest common factor in 8 and 2.
x ^ 2 -\frac{3}{2}x -1 = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.This is achieved by dividing both sides of the equation by 8
r + s = \frac{3}{2} rs = -1
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = \frac{3}{4} - u s = \frac{3}{4} + u
Two numbers r and s sum up to \frac{3}{2} exactly when the average of the two numbers is \frac{1}{2}*\frac{3}{2} = \frac{3}{4}. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(\frac{3}{4} - u) (\frac{3}{4} + u) = -1
To solve for unknown quantity u, substitute these in the product equation rs = -1
\frac{9}{16} - u^2 = -1
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = -1-\frac{9}{16} = -\frac{25}{16}
Simplify the expression by subtracting \frac{9}{16} on both sides
u^2 = \frac{25}{16} u = \pm\sqrt{\frac{25}{16}} = \pm \frac{5}{4}
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =\frac{3}{4} - \frac{5}{4} = -0.500 s = \frac{3}{4} + \frac{5}{4} = 2
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.