Solve 8x^2+9x+j=0

$$8 x ^ { 2 } + 9 x + j = 0$$

Solve for j

$$j=-x\left(8x+9\right)$$

Solution Steps

Subtract 8x^{2} from both sides. Anything subtracted from zero gives its negation.

$$9x+j=-8x^{2}$$

Subtract 9x from both sides.

$$j=-8x^{2}-9x$$

Solve for x (complex solution)

$$x=\frac{\sqrt{81-32j}-9}{16}$$

$$x=\frac{-\sqrt{81-32j}-9}{16}$$

Solve for x

$$x=\frac{\sqrt{81-32j}-9}{16}$$

$$x=\frac{-\sqrt{81-32j}-9}{16}\text{, }j\leq \frac{81}{32}$$