Solve 8x^2+43x+44

$$8 x ^ { 2 } + 43 x + 44$$

Factor

$$\left(x+4\right)\left(8x+11\right)$$

Solution Steps

Factor the expression by grouping. First, the expression needs to be rewritten as 8x^{2}+ax+bx+44. To find a and b, set up a system to be solved.

$$a+b=43 ab=8\times 44=352$$

Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 352.

$$1,352 2,176 4,88 8,44 11,32 16,22$$

Calculate the sum for each pair.

$$1+352=353 2+176=178 4+88=92 8+44=52 11+32=43 16+22=38$$

The solution is the pair that gives sum 43.

$$a=11 b=32$$

Rewrite 8x^{2}+43x+44 as \left(8x^{2}+11x\right)+\left(32x+44\right).

$$\left(8x^{2}+11x\right)+\left(32x+44\right)$$

Factor out x in the first and 4 in the second group.

$$x\left(8x+11\right)+4\left(8x+11\right)$$

Factor out common term 8x+11 by using distributive property.

$$\left(8x+11\right)\left(x+4\right)$$

Steps Using the Quadratic Formula

Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where x_{1} and x_{2} are the solutions of the quadratic equation ax^{2}+bx+c=0.

$$8x^{2}+43x+44=0$$

All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

$$x=\frac{-43±\sqrt{43^{2}-4\times 8\times 44}}{2\times 8}$$

Square 43.

$$x=\frac{-43±\sqrt{1849-4\times 8\times 44}}{2\times 8}$$

Multiply -4 times 8.

$$x=\frac{-43±\sqrt{1849-32\times 44}}{2\times 8}$$

Multiply -32 times 44.

$$x=\frac{-43±\sqrt{1849-1408}}{2\times 8}$$

Add 1849 to -1408.

$$x=\frac{-43±\sqrt{441}}{2\times 8}$$

Take the square root of 441.

$$x=\frac{-43±21}{2\times 8}$$

Multiply 2 times 8.

$$x=\frac{-43±21}{16}$$

Now solve the equation x=\frac{-43±21}{16} when ± is plus. Add -43 to 21.

$$x=-\frac{22}{16}$$

Reduce the fraction \frac{-22}{16} to lowest terms by extracting and canceling out 2.

$$x=-\frac{11}{8}$$

Now solve the equation x=\frac{-43±21}{16} when ± is minus. Subtract 21 from -43.

$$x=-\frac{64}{16}$$

Divide -64 by 16.

$$x=-4$$

Factor the original expression using ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Substitute -\frac{11}{8} for x_{1} and -4 for x_{2}.

$$8x^{2}+43x+44=8\left(x-\left(-\frac{11}{8}\right)\right)\left(x-\left(-4\right)\right)$$

Simplify all the expressions of the form p-\left(-q\right) to p+q.

$$8x^{2}+43x+44=8\left(x+\frac{11}{8}\right)\left(x+4\right)$$

Add \frac{11}{8} to x by finding a common denominator and adding the numerators. Then reduce the fraction to lowest terms if possible.

$$8x^{2}+43x+44=8\times \frac{8x+11}{8}\left(x+4\right)$$

Cancel out 8, the greatest common factor in 8 and 8.

$$8x^{2}+43x+44=\left(8x+11\right)\left(x+4\right)$$

Steps Using Direct Factoring Method

Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.This is achieved by dividing both sides of the equation by 8

$$x ^ 2 +\frac{43}{8}x +\frac{11}{2} = 0$$

Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C

$$r + s = -\frac{43}{8} rs = \frac{11}{2}$$

Two numbers r and s sum up to -\frac{43}{8} exactly when the average of the two numbers is \frac{1}{2}*-\frac{43}{8} = -\frac{43}{16}. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>

$$r = -\frac{43}{16} - u s = -\frac{43}{16} + u$$

To solve for unknown quantity u, substitute these in the product equation rs = \frac{11}{2}

$$(-\frac{43}{16} - u) (-\frac{43}{16} + u) = \frac{11}{2}$$

Simplify by expanding (a -b) (a + b) = a^2 – b^2

$$\frac{1849}{256} - u^2 = \frac{11}{2}$$

Simplify the expression by subtracting \frac{1849}{256} on both sides

$$-u^2 = \frac{11}{2}-\frac{1849}{256} = -\frac{441}{256}$$

Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u

$$u^2 = \frac{441}{256} u = \pm\sqrt{\frac{441}{256}} = \pm \frac{21}{16}$$

The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.

$$r =-\frac{43}{16} - \frac{21}{16} = -4 s = -\frac{43}{16} + \frac{21}{16} = -1.375$$

Evaluate

$$\left(x+4\right)\left(8x+11\right)$$