Solve 8x^2+3x-h=0

$$8 x ^ { 2 } + 3 x - h = 0$$

Solve for h

$$h=x\left(8x+3\right)$$

Steps for Solving Linear Equation

Subtract 8x^{2} from both sides. Anything subtracted from zero gives its negation.

$$3x-h=-8x^{2}$$

Subtract 3x from both sides.

$$-h=-8x^{2}-3x$$

Divide both sides by -1.

$$\frac{-h}{-1}=-\frac{x\left(8x+3\right)}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$h=-\frac{x\left(8x+3\right)}{-1}$$

Divide -x\left(3+8x\right) by -1.

$$h=x\left(8x+3\right)$$

Solve for x (complex solution)

$$x=\frac{\sqrt{32h+9}-3}{16}$$

$$x=\frac{-\sqrt{32h+9}-3}{16}$$

Solve for x

$$x=\frac{\sqrt{32h+9}-3}{16}$$

$$x=\frac{-\sqrt{32h+9}-3}{16}\text{, }h\geq -\frac{9}{32}$$