Solve for x
x = -\frac{7}{4} = -1\frac{3}{4} = -1.75
x=\frac{1}{2}=0.5
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a+b=10 ab=8\left(-7\right)=-56
To solve the equation, factor the left hand side by grouping. First, left hand side needs to be rewritten as 8x^{2}+ax+bx-7. To find a and b, set up a system to be solved.
-1,56 -2,28 -4,14 -7,8
Since ab is negative, a and b have the opposite signs. Since a+b is positive, the positive number has greater absolute value than the negative. List all such integer pairs that give product -56.
-1+56=55 -2+28=26 -4+14=10 -7+8=1
Calculate the sum for each pair.
a=-4 b=14
The solution is the pair that gives sum 10.
\left(8x^{2}-4x\right)+\left(14x-7\right)
Rewrite 8x^{2}+10x-7 as \left(8x^{2}-4x\right)+\left(14x-7\right).
4x\left(2x-1\right)+7\left(2x-1\right)
Factor out 4x in the first and 7 in the second group.
\left(2x-1\right)\left(4x+7\right)
Factor out common term 2x-1 by using distributive property.
x=\frac{1}{2} x=-\frac{7}{4}
To find equation solutions, solve 2x-1=0 and 4x+7=0.
8x^{2}+10x-7=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-10±\sqrt{10^{2}-4\times 8\left(-7\right)}}{2\times 8}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 8 for a, 10 for b, and -7 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-10±\sqrt{100-4\times 8\left(-7\right)}}{2\times 8}
Square 10.
x=\frac{-10±\sqrt{100-32\left(-7\right)}}{2\times 8}
Multiply -4 times 8.
x=\frac{-10±\sqrt{100+224}}{2\times 8}
Multiply -32 times -7.
x=\frac{-10±\sqrt{324}}{2\times 8}
Add 100 to 224.
x=\frac{-10±18}{2\times 8}
Take the square root of 324.
x=\frac{-10±18}{16}
Multiply 2 times 8.
x=\frac{8}{16}
Now solve the equation x=\frac{-10±18}{16} when ± is plus. Add -10 to 18.
x=\frac{1}{2}
Reduce the fraction \frac{8}{16} to lowest terms by extracting and canceling out 8.
x=-\frac{28}{16}
Now solve the equation x=\frac{-10±18}{16} when ± is minus. Subtract 18 from -10.
x=-\frac{7}{4}
Reduce the fraction \frac{-28}{16} to lowest terms by extracting and canceling out 4.
x=\frac{1}{2} x=-\frac{7}{4}
The equation is now solved.
8x^{2}+10x-7=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
8x^{2}+10x-7-\left(-7\right)=-\left(-7\right)
Add 7 to both sides of the equation.
8x^{2}+10x=-\left(-7\right)
Subtracting -7 from itself leaves 0.
8x^{2}+10x=7
Subtract -7 from 0.
\frac{8x^{2}+10x}{8}=\frac{7}{8}
Divide both sides by 8.
x^{2}+\frac{10}{8}x=\frac{7}{8}
Dividing by 8 undoes the multiplication by 8.
x^{2}+\frac{5}{4}x=\frac{7}{8}
Reduce the fraction \frac{10}{8} to lowest terms by extracting and canceling out 2.
x^{2}+\frac{5}{4}x+\left(\frac{5}{8}\right)^{2}=\frac{7}{8}+\left(\frac{5}{8}\right)^{2}
Divide \frac{5}{4}, the coefficient of the x term, by 2 to get \frac{5}{8}. Then add the square of \frac{5}{8} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+\frac{5}{4}x+\frac{25}{64}=\frac{7}{8}+\frac{25}{64}
Square \frac{5}{8} by squaring both the numerator and the denominator of the fraction.
x^{2}+\frac{5}{4}x+\frac{25}{64}=\frac{81}{64}
Add \frac{7}{8} to \frac{25}{64} by finding a common denominator and adding the numerators. Then reduce the fraction to lowest terms if possible.
\left(x+\frac{5}{8}\right)^{2}=\frac{81}{64}
Factor x^{2}+\frac{5}{4}x+\frac{25}{64}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+\frac{5}{8}\right)^{2}}=\sqrt{\frac{81}{64}}
Take the square root of both sides of the equation.
x+\frac{5}{8}=\frac{9}{8} x+\frac{5}{8}=-\frac{9}{8}
Simplify.
x=\frac{1}{2} x=-\frac{7}{4}
Subtract \frac{5}{8} from both sides of the equation.
x ^ 2 +\frac{5}{4}x -\frac{7}{8} = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.This is achieved by dividing both sides of the equation by 8
r + s = -\frac{5}{4} rs = -\frac{7}{8}
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = -\frac{5}{8} - u s = -\frac{5}{8} + u
Two numbers r and s sum up to -\frac{5}{4} exactly when the average of the two numbers is \frac{1}{2}*-\frac{5}{4} = -\frac{5}{8}. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(-\frac{5}{8} - u) (-\frac{5}{8} + u) = -\frac{7}{8}
To solve for unknown quantity u, substitute these in the product equation rs = -\frac{7}{8}
\frac{25}{64} - u^2 = -\frac{7}{8}
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = -\frac{7}{8}-\frac{25}{64} = -\frac{81}{64}
Simplify the expression by subtracting \frac{25}{64} on both sides
u^2 = \frac{81}{64} u = \pm\sqrt{\frac{81}{64}} = \pm \frac{9}{8}
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =-\frac{5}{8} - \frac{9}{8} = -1.750 s = -\frac{5}{8} + \frac{9}{8} = 0.500
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.
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