Solve 8x=-4-4x^2b

$$8 x = - 4 - 4 x ^ { 2 } b$$

Solve for b

$$b=-\frac{2x+1}{x^{2}}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$-4-4x^{2}b=8x$$

Add 4 to both sides.

$$-4x^{2}b=8x+4$$

The equation is in standard form.

$$\left(-4x^{2}\right)b=8x+4$$

Divide both sides by -4x^{2}.

$$\frac{\left(-4x^{2}\right)b}{-4x^{2}}=\frac{8x+4}{-4x^{2}}$$

Dividing by -4x^{2} undoes the multiplication by -4x^{2}.

$$b=\frac{8x+4}{-4x^{2}}$$

Divide 8x+4 by -4x^{2}.

$$b=-\frac{2x+1}{x^{2}}$$

Solve for x (complex solution)

$$\left\{\begin{matrix}x=\frac{\sqrt{1-b}-1}{b}\text{; }x=-\frac{\sqrt{1-b}+1}{b}\text{, }&b\neq 0\\x=-\frac{1}{2}\text{, }&b=0\end{matrix}\right.$$

Solve for x

$$\left\{\begin{matrix}x=\frac{\sqrt{1-b}-1}{b}\text{; }x=-\frac{\sqrt{1-b}+1}{b}\text{, }&b\neq 0\text{ and }b\leq 1\\x=-\frac{1}{2}\text{, }&b=0\end{matrix}\right.$$